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Merge pull request #1530 from Raj-Parekh24/master
Longest Increasing Subsequence using DP
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""" | ||
Given an integer array nums, return the length of the longest strictly increasing subsequence. | ||
A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements. For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7]. | ||
Example 1: | ||
Input: nums = [10,9,2,5,3,7,101,18] | ||
Output: 4 | ||
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. | ||
Example 2: | ||
Input: nums = [0,1,0,3,2,3] | ||
Output: 4 | ||
Example 3: | ||
Input: nums = [7,7,7,7,7,7,7] | ||
Output: 1 | ||
""" | ||
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import java.util.*; | ||
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class Solution { | ||
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public static int lengthOfLIS(int[] a) { | ||
int dp[]=new int[a.length+1]; | ||
Arrays.fill(dp,1); | ||
for(int i=1;i<=a.length;i++){ | ||
int max=0; | ||
for(int j=1;j<i;j++){ | ||
if(a[j-1]<a[i-1]){ | ||
max=Math.max(max,dp[j]); | ||
} | ||
} | ||
dp[i]=max+1; | ||
} | ||
int ans=0; | ||
for(int i:dp) | ||
ans=Math.max(ans,i); | ||
return ans; | ||
} | ||
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public static void main(String[] args){ | ||
Scanner sc=new Scanner(System.in); | ||
System.out.println("Enter the size of array :- "); | ||
int a=sc.nextInt(); | ||
int arr[]=new int[a]; | ||
System.out.println("Enter the elements of array :- "); | ||
for(int i=0;i<a;i++){ | ||
arr[i]=sc.nextInt(); | ||
} | ||
System.out.println("The maximum array size with increasing subsequence is :- "+lengthOfLIS(arr)); | ||
} | ||
} |