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Merge pull request #592 from TonyKim9401/main
[Tony] WEEK 14 Solutions
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// TC: O(n) | ||
// need to visit all nodes | ||
// SC: O(n) | ||
// normally O(log n) required however, O(n) in the worst case | ||
class Solution { | ||
private List<List<Integer>> output = new ArrayList<>(); | ||
public List<List<Integer>> levelOrder(TreeNode root) { | ||
dfs(0, root); | ||
return output; | ||
} | ||
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private void dfs(int level, TreeNode node) { | ||
if (node == null) return; | ||
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if (output.size() == level) { | ||
List<Integer> inside = new ArrayList<>(); | ||
inside.add(node.val); | ||
output.add(inside); | ||
} else { | ||
output.get(level).add(node.val); | ||
} | ||
level += 1; | ||
dfs(level, node.left); | ||
dfs(level, node.right); | ||
} | ||
} |
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// TC: O(n) | ||
// visit all nums at least once | ||
// SC: O(1) | ||
// only constant memory space required | ||
class Solution { | ||
public int rob(int[] nums) { | ||
if (nums.length == 1) return nums[0]; | ||
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int prev = 0; | ||
int post = 0; | ||
int output1 = 0; | ||
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for (int i = 0; i < nums.length - 1; i++) { | ||
int temp = prev; | ||
prev = Math.max(post + nums[i], prev); | ||
post = temp; | ||
} | ||
output1 = prev; | ||
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prev = 0; | ||
post = 0; | ||
int output2 = 0; | ||
for (int i = 1; i < nums.length; i++) { | ||
int temp = prev; | ||
prev = Math.max(post + nums[i], prev); | ||
post = temp; | ||
} | ||
output2 = prev; | ||
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return Math.max(output1, output2); | ||
} | ||
} |
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// TC: O(n) | ||
// visit all intervals to compare each of start time | ||
// SC: O(n) | ||
// PQ save all intervals in the worst case | ||
public class Solution { | ||
public int minMeetingRooms(List<Interval> intervals) { | ||
if (intervals == null || intervals.isEmpty()) return 0; | ||
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intervals.sort((a, b) -> a.start - b.start); | ||
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PriorityQueue<Integer> endTimes = new PriorityQueue<>(); | ||
endTimes.add(intervals.get(0).end); | ||
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for (int i = 1; i < intervals.size(); i++) { | ||
Interval current = intervals.get(i); | ||
if (current.start >= endTimes.peek()) endTimes.poll(); | ||
endTimes.add(current.end); | ||
} | ||
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return endTimes.size(); | ||
} | ||
} |
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public class Solution { | ||
public int reverseBits(int n) { | ||
// time complexity O(1) | ||
// space complexity O(1) | ||
int output = 0; | ||
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for (int i = 0; i < Integer.SIZE; i++) { | ||
output <<= 1; | ||
output += n & 1; | ||
n >>= 1; | ||
} | ||
return output; | ||
} | ||
} |