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Arithmetic_Subarrays.cpp
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PROBLEM STATEMENT :-
A sequence of numbers is called arithmetic if it consists of at least two elements, and the difference between every two consecutive elements is the same.
More formally, a sequence s is arithmetic if and only if s[i+1] - s[i] == s[1] - s[0] for all valid i.
For example, these are arithmetic sequences:
1, 3, 5, 7, 9
7, 7, 7, 7
3, -1, -5, -9
The following sequence is not arithmetic:
1, 1, 2, 5, 7
You are given an array of n integers, nums, and two arrays of m integers each, l and r, representing the m range queries, where the ith query is the range [l[i], r[i]].
All the arrays are 0-indexed.
Return a list of boolean elements answer, where answer[i] is true if the subarray nums[l[i]], nums[l[i]+1], ... , nums[r[i]] can be rearranged to form an arithmetic sequence,
and false otherwise.
Example 1:
Input: nums = [4,6,5,9,3,7], l = [0,0,2], r = [2,3,5]
Output: [true,false,true]
Explanation:
In the 0th query, the subarray is [4,6,5]. This can be rearranged as [6,5,4], which is an arithmetic sequence.
In the 1st query, the subarray is [4,6,5,9]. This cannot be rearranged as an arithmetic sequence.
In the 2nd query, the subarray is [5,9,3,7]. This can be rearranged as [3,5,7,9], which is an arithmetic sequence.
SOLUTION :-
class Solution {
public:
vector<bool> checkArithmeticSubarrays(vector<int>& nums, vector<int>& l, vector<int>& r)
{
vector<bool> res;
for(int i=0;i<l.size();i++)
{
vector<int> ans;
for(int w=l[i];w<=r[i] ;w++)
{
ans.push_back(nums[w]);
}
sort(ans.begin(),ans.end());
if(ans.size()==1)
res.push_back(true);
else
{
int k=ans[1]-ans[0];
bool f=true;
for(int p=2;p<ans.size();p++)
{
int diff=ans[p]-ans[p-1];
if(diff!=k)
{
res.push_back(false);
f=false;
break;
}
}
if(f==true)
res.push_back(true);
}
}
return res;
}
};