Choose the number of channels with LyonCalc(

[David-GERARD]

Hi,

I'm using the code in this repository to process audio files recorded at 8kH of various lengths.
I would like all my cochleograms to have the same number of channel, that I would like to be able to specify.

So far, I have been able to do so by adjusting the step_factor, but I was wandering if there was a better more deterministic way to do that.

Best regards,
David

[David-GERARD]

The number of channel is computed in utils.design_lyon_filters, line 50 of utils.py

NumberOfChannels = np.floor((ear_q*(-_log_val_low + _log_val_top))/step_factor)

Is the idea of fixing the number of channel and instead computing ear_q or the step factor bad?