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implement-stack-using-queues.py
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# -*- coding: utf-8 -*-
"""
Created on Sat Apr 25 00:36:16 2020
@author: johnoyegbite
"""
# SOLVED!
"""
Problem:
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
Notes:
You must use only standard operations of a queue -- which means only push
to back, peek/pop from front, size, and is empty operations are valid.
Depending on your language, queue may not be supported natively.
You may simulate a queue by using a list or deque (double-ended queue),
as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top
operations will be called on an empty stack).
"""
from queue import Queue
class MyStack:
def __init__(self):
"""
Initialize your data structure here.
"""
self.last = None # top element on the stack
self.size = 0
self.q1 = Queue()
self.q2 = Queue()
def push(self, x: int) -> None:
"""
Push element x onto stack.
"""
self.q1.put(x)
self.last = x
self.size += 1
def pop(self) -> int:
"""
Removes the element on top of the stack and returns that element.
"""
# copy the current size to control the last element that would be
# popped.
size = self.size
while not self.q1.empty():
x = self.q1.get()
if size > 1:
self.q2.put(x)
self.last = x
size -= 1
self.size -= 1 # elemnet in the size is reduced by 1
self.q1, self.q2 = self.q2, self.q1
return x
def top(self) -> int:
"""
Get the top element.
"""
return self.last
def empty(self) -> bool:
"""
Returns whether the stack is empty.
"""
return self.size <= 0
# Your MyStack object will be instantiated and called as such:
# obj = MyStack()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.top()
# param_4 = obj.empty()