-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path450.删除二叉搜索树中的节点.js
67 lines (62 loc) · 1.6 KB
/
450.删除二叉搜索树中的节点.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
/*
* @lc app=leetcode.cn id=450 lang=javascript
*
* [450] 删除二叉搜索树中的节点
*/
// @lc code=start
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @param {number} key
* @return {TreeNode}
*/
var deleteNode = function(root, key) {
return helper(root, key)
function helper(root, key) {
// base case
if (root == null) return null
if (root.val === key) {
// s1: root is leaf node
if (root.left == null && root.right == null) {
return null // deleteNode directly
}
// s2: root has left or right
if (root.left === null) {
return root.right
}
if (root.right === null) {
return root.left
}
// s3: root has two child nodes, now we have two choices
// 1. find the largest node in the left 2. find the smallest node in the right
if (root.left && root.right) {
const minNode = getMin(root.right)
root.right = helper(root.right, minNode.val)
minNode.left = root.left
minNode.right = root.right
root = minNode
}
} else if (root.val < key) {
root.right = helper(root.right, key)
} else if (root.val > key) {
root.left = helper(root.left, key)
}
return root
}
function getMin(root) {
let p = root
while (p.left) {
p = p.left
}
return p
}
}
// @lc code=end
module.exports = { deleteNode }