Given an array nums
of n integers, are there elements a, b, c in nums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
Tags: Array, Two Pointers
从数组中找出所有三个和为 0 的元素构成的非重复序列
我们可以把数组先做下排序,然后遍历这个排序数组,用两个指针分别指向当前元素的下一个和数组尾部,判断三者的和与 0 的大小来移动两个指针,其中细节操作就是优化和去重。
func threeSum(nums []int) [][]int {
ans := [][]int{}
if len(nums) <= 2 {
return ans
}
// 排序
sort.Ints(nums)
for i := 0; i < len(nums)-2; i++ {
if i == 0 || (i > 0 && nums[i] != nums[i-1]) {
low, high, sum := i+1, len(nums)-1, 0-nums[i]
for low < high {
// 和为0的时候
if nums[low]+nums[high] == sum {
ans = append(ans, []int{nums[i], nums[low], nums[high]})
// 排除;连续相等的数
for low < high && nums[low] == nums[low+1] {
low++
}
for low < high && nums[high] == nums[high-1] {
high--
}
low++
high--
} else if nums[low]+nums[high] < sum {
low++
} else {
high--
}
}
}
}
return ans
}
思路2 ```go
```
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